Geometry Test # 2 ( Distance/Midpoint)

What must you know to find the midpoint, distance or fractional distance of a line?

• An endpoint

• endpoints

• A rate

• The slope

The __________ of a line i a bisector of the line and creates two congruent line segments

• endpoint

• ray

• bisector

• midpoint

The ________ is how far it is between two points and does not depend on the value of the numbers.

• Coordinate plane

• End Point

• Distance

• Ray

Point P (_____, _____) is $\frac{2}{3}$ the distance from B to A. 

• (0, 3)

• (-4, -1)

• (1, 4)

• (-5, -2)

What is the coordinate of so that point Q is $\frac{2}{5}$ the distance from B to A. 

• -17

• -14

• -11

• -8

What is the distance between the points (-2, 5) and (4, -3)?. Round to the nearest tenth.

(-2,5) and (4, -3)

• 9.0

• 10

• 5.7

• 5.8

(-3, 2) and (12, 10) are points on opposite ends of the diameter of a circle. Round to the nearest tenth.

• 2.9

• 5.7

• 17

• 4.6

Find the distance between the points. Round to the nearest tenth.

(2,5) and (3,7)

• 6.7

• 2.2

• 4.5

• 3.6

How is the distance formula correctly written:

• $d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\$

• $d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)2}$

• $d\ =\ \sqrt{\left(y_{1\ }-\ y\ _2\right)^2\ +\ \left(x_{2\ }-\ x_1\right)}^2$

• d = $\sqrt{\left(x\right)^2-\ \left(y\right)^2}$

A(3,1) B(-2,-1) written correctly is:

• $\sqrt{\left(-2-3\right)^2\ +\ \left(-1-1\right)^2}$

• $\sqrt{\left(1-3\right)^2\ +\ \left(-1-2\right)^2}$

• $\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}$

• $\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}$