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SUMATIF TENGAH SEMESTER (TRANSFORMASI FUNGSI)

Authored by Shilahudin Khumaidi

Mathematics

12th Grade

Used 8+ times

SUMATIF TENGAH SEMESTER (TRANSFORMASI FUNGSI)
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15 questions

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1.

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Diketahui fungsi y = 3x2 – 4 ditranslasikan oleh (0,3). Hasil traslasi fungsi adalah…

y = 3x2 – 1

y = 3x2 – 2

y = 3x2 – 18x + 23

y = 4x2 – 15x + 23

y = 6x2 + 12x + 23

2.

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Fungsi y= x3- 6x2 + 4x + 12 di rotasikan sebesar 900 searah jarum jam terhadap titik pusat (0,0). Hasil rotasi fungsi tersebut adalah…..

x= y3 + 6y2 + 4y + 12

x= y3 - 6y2 - 4y + 12

x= y3 + 6y2 - 4y - 12

x= - y3 -  6y2 - 4y + 12

x= -y3 + 6y2 - 4y - 12

3.

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Fungsi y = x2+2  digeser ke kiri sejauh 3 satuan dilanjutkan digeser ke atas sejauh 1 satuan persamaan hasil komposisi traslasi fungsi tersebut adalah …

y = ( x+ 3)2+ 3

y = ( x+ 3)2+ 1

y = ( x+ 3)2 - 3

y = ( x- 3)2+ 3

y = ( x - 3)2 - 1

4.

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Garis p: 2x +3y + 6 = 0 direfleksikan terhadap sumbu x, lalu direflesikan terhadap sumbu y. persaman garis hasil komposisi trasformasi tersebut adalah…

2x + 3y – 6 = 0

- 2x - 3y + 6 = 0

2x - 3y – 6 = 0

2x + 3y - 6 = 0

2x + 3y + 6 = 0

5.

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Diketahui fungsi  kuadrat F(x) = x2 + 4x – 6 mengalami dilatasi vertikal dengan faktor skala 3 . Fungsi hasil dilatasi adalah ..

f(X) = 3x2 + 12x – 18

f(X) = x2 + 4x – 6

f(X) = x2 + 16x – 24

f(X) = 9x2 + 12x – 6

f(X) = 9x2 + 14 + 12

6.

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Fungsi  f(x) = 4x2 – 3x + 6 ditranslasikan oleh T = (0, -3). Hasil translasi fungsi tersebut adalah…

f(X) = 4x2 - 3x – 9

f(X) = 4x2 - 3x – 3

f(X) = 4x2 - 3x + 3

f(X) = 4x2 - 3x  + 7

f(X) = 4x2 - 3x + 9

7.

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Fungsi f(x) = 2x digeser 6 satuan ke kanan persamaan fungsi translasi adalah….

f(x) = 2x+3

f(x) = 2x- 3

f(x) = 2x

f(x) = 2x+6

f(x) = 2x-6

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