What is the condition for using a geometric formula to evaluate a definite integral?

Evaluating Definite Integrals and Geometry

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Lucas Foster
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Mathematics
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9th - 12th Grade
•
Hard
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The function must be periodic and bounded.
The function must be quadratic and positive.
The function must be continuous and non-negative on a closed interval.
The function must be linear and increasing.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the function used in the example for evaluating the definite integral?
y = 5x + 1
y = x^2 - 4
y = 3/2x - 3
y = 2x + 3
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the y-intercept of the function y = 3/2x - 3?
6
0
3
-3
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the slope of the function y = 3/2x - 3?
By dividing the change in y by the change in x.
By finding the x-intercept.
By calculating the derivative.
By setting y to zero.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What geometric shape is used to calculate the area under the curve from 0 to 2?
Rectangle
Triangle
Trapezoid
Circle
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is the area from 0 to 2 considered negative?
Because the function is below the x-axis.
Because the function is above the x-axis.
Because the function is decreasing.
Because the function is increasing.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the base length of the larger blue triangle from 2 to 6?
2
4
6
8
8.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the height of the larger blue triangle from 2 to 6?
6
4
3
5
9.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final value of the definite integral from 0 to 6 of 3/2x - 3?
6
9
12
15
10.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the key takeaway from evaluating the definite integral using geometric formulas?
The integral is always positive.
Negative areas can be ignored.
Only positive areas contribute to the integral.
Negative areas must be accounted for by making them negative in the calculation.
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