Writing the equation of a straight line

Write an equation of a line perpendicular to
y = 7x +1 through (-4, 0)

• y = 1/7x - 4/7
• y = -1/7x - 4/7
• y = 2/7x - 4/7
• y = -4/7x + 2/7

Write the equation of a line that contains the point (3, 5) and has a slope of 3 in slope-intercept form.

• y = 3x - 4
• y - 5 = 3(x-3)
• y = 3x + 14
• y + 5 = 3(x+3)

Write the point-slope form of the equation of the line through the given point with the given slope.

through: (4, 1), slope = -1

• y - 4 = x - 1

• None of these

• y - 1 = -(x + 4)

• y - 1 = -(x - 4)

What is the point-slope form of the given information:

 $through:(-4,1),\ slope=-\frac{1}{2}$  

•  $y\ +\ 1\ =\ -\frac{1}{2}\left(x\ +\ 4\right)$  

•  $y\ +\ 1\ =\ -\frac{2}{1}\left(x\ +\ 4\right)$  

Which of these represents point-slope form of a linear equation?

• y - y₁ = m(x - x₁)
• Ax + By = C
• y = mx + b
• y=kx

Write the slope-intercept form of the equation shown in the graph.

• y = -2/3x + 4

• 
  y = 2/3x + 4

• y = 3/2x + 4

• y = -3/2x + 4

Write the equation in point-slope form of the line that passes through the given point and has the given slope. (2, 5); m = -3

• y +3 = 5(x - 2)

• y - 5 = -3(x - 2)

• y+ 5 = -3(x +2)

• y - 2 = 5(x - 3)

What is point-slope formula

• y - y₁ = m (x - x₁)

• x - x₁ = m (y - y₁)

• y - y₁ = m (y - y₁)