MAT 471 Online Tool (Trig)

Solve for x:

sin(90)=5/x

(Degree Mode)

• x = 1

• x = 5

• x = 90

• x = 5.59

Tags

CCSS.HSG.SRT.C.8

CCSS.HSF.TF.B.7

What kind of triangle is shown?

• Obtuse

• Scalene

• Isosceles

• Right

Tags

CCSS.4.G.A.2

Solve for x

• x = 12.5

• x = 15.9

• x = 16.3

• x = 13.8

Tags

CCSS.HSG.SRT.C.8

CCSS.HSF.TF.A.3

What Formula is shown?

• Area of a Triangle

• Perimeter of a Triangle

• Volume of a Cone

• Pythagorean Theorem

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.B.4

Cosine Formula

• Adjacent/Hypotenuse

• Opposite/Hypotenuse

• Adjacent/Opposite

• Opposite/Adjacent

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6

Sine Formula

• Adjacent/Hypotenuse

• Opposite/Hypotenuse

• Hypotenuse/Opposite

• Hypotenuse/Adjacent

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6

CCSS.HSF.TF.A.2

Tangent Formula

• Opposite/Hypotenuse

• Adjacent/Hypotenuse

• Opposite/Adjacent

• Adjacent/Opposite

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6

Select the correct ratio for SinA

• $\frac{37}{35}$

• $\frac{12}{35}$

• $\frac{35}{37}$

• $\frac{12}{37}$

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.D.11

Which is the correct applied ratio?

• A

• B

• C

• D

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6

Which is the correct applied ratio?

• A

• B

• C

• D

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6