Vertex Form of Quadratics

up/down

left/right

slope/width

(3, 5)

(-3, 5)

(3, -5)

(-3, -5)

$$p\left(x\right)=\frac{5}{3}x^2-1$$  

$$f\left(x\right)=x^2-5$$  

$$q\left(x\right)=-\frac{6}{5}\left(x+1\right)^2+5$$  

$$a\left(x\right)=-x^2+4$$  

$$g\left(x\right)=\frac{1}{3}\left(x-2\right)^2+4$$  

$$b\left(x\right)=4\left(x-1\right)^2$$  

$$h\left(x\right)=-\frac{1}{2}\left(x-3\right)^2$$  

$$g\left(x\right)=\frac{1}{3}\left(x-2\right)^2+4$$  

$$p\left(x\right)=\frac{5}{3}x^2-1$$  

$$b\left(x\right)=4\left(x-1\right)^2$$  

$$h\left(x\right)=-\frac{1}{2}\left(x-3\right)^2$$  

$$f\left(x\right)=x^2-5$$  

$$a\left(x\right)=-x^2+4$$  

$$q\left(x\right)=-6\left(x+1\right)^2+5$$  

$$y=-2\left(x-1\right)^2+3$$

$$y=2\left(x-1\right)^2+3$$

$$y=2\left(x+1\right)^2+3$$

$$y=-2\left(x+1\right)^2+3$$

$$y=\frac{1}{3}\left(x-2\right)^2-1$$

$$y=\frac{1}{3}\left(x+2\right)^2-1$$

$$y=-\frac{1}{3}\left(x+2\right)^2-1$$

$$y=-\frac{1}{3}\left(x-2\right)^2-1$$