Solving Quadratics by Taking Square Roots

Solving Quadratics by Taking Square Roots

Assessment

Flashcard

Mathematics

8th Grade

Hard

CCSS
HSA-REI.B.4B, 8.EE.A.2, HSF-IF.C.7A

Standards-aligned

Created by

Wayground Content

FREE Resource

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the general form of a quadratic equation?

Back

The general form of a quadratic equation is ax² + bx + c = 0, where a, b, and c are constants and a ≠ 0.

2.

FLASHCARD QUESTION

Front

What does it mean to solve a quadratic equation by taking square roots?

Back

Solving a quadratic equation by taking square roots involves isolating the x² term and then applying the square root to both sides of the equation, resulting in two possible solutions: x = ±√(value).

Tags

CCSS.HSA-REI.B.4B

3.

FLASHCARD QUESTION

Front

What is the square root of 64?

Back

The square root of 64 is 8, and since we consider both positive and negative roots, the solutions are x = 8 and x = -8.

Tags

CCSS.8.EE.A.2

4.

FLASHCARD QUESTION

Front

How do you isolate x² in the equation 3x² - 27 = 0?

Back

To isolate x², first add 27 to both sides to get 3x² = 27, then divide both sides by 3 to obtain x² = 9.

Tags

CCSS.8.EE.A.2

5.

FLASHCARD QUESTION

Front

What are the solutions to the equation x² = 9?

Back

The solutions to the equation x² = 9 are x = 3 and x = -3.

Tags

CCSS.8.EE.A.2

6.

FLASHCARD QUESTION

Front

What is the first step in solving the equation 5m² + 1 = 6?

Back

The first step is to subtract 1 from both sides to isolate the term with m², resulting in 5m² = 5.

Tags

CCSS.8.EE.A.2

7.

FLASHCARD QUESTION

Front

How do you solve for m in the equation 5m² = 5?

Back

Divide both sides by 5 to get m² = 1, then take the square root of both sides to find m = ±1.

Tags

CCSS.8.EE.A.2

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