Trigonometric Identities Review

Quiz
•
Mathematics
•
9th - 12th Grade
•
Hard
Standards-aligned
Amanda Funk
Used 3+ times
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To multiply the expression \( \frac{\frac{1}{\sin x}}{\cos x} \), we rewrite it as \( \frac{1}{\sin x} \cdot \frac{1}{\cos x} \). Thus, the correct choice is \( \frac{1}{\sin x} \cdot \frac{1}{\cos x} \).
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To simplify \( \frac{\sin x}{\frac{1}{\cos x}} \), multiply by the reciprocal: \( \sin x \cdot \cos x \). Thus, the correct choice is \( \sin x \cdot \cos x \).
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
The common denominator for \( \frac{1}{\cos^2x} + \frac{1}{\sin^2x} \) is the product of the individual denominators, which is \( \cos^2x \cdot \sin^2x \). Thus, the correct answer is \( \cos^2x \cdot \sin^2x \).
4.
MULTIPLE SELECT QUESTION
1 min • 1 pt
Select ALL that are a variation of a Pythagorean Identity.
Answer explanation
The Pythagorean identity states \(\sin^2x + \cos^2x = 1\). The equation \(1 - \cos^2x = \sin^2x\) is derived from it. The other options are not valid variations of the Pythagorean identity.
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Pythagorean Identity
Multiply by the conjugate
Factor
Break the fraction apart
Answer explanation
To simplify \( \frac{\sin^2x+1}{\sin x} \), breaking the fraction apart is effective. This allows us to separate it into \( \frac{\sin^2x}{\sin x} + \frac{1}{\sin x} \), simplifying to \( \sin x + \csc x \).
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To simplify \( \frac{\sin x}{\frac{1}{\cos x}} \), multiply by the reciprocal: \( \sin x \cdot \cos x \). Thus, the correct choice is \( \sin x \cdot \cos x \).
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
sin2θ=
1 - cos2θ
1 - sin2θ
sec2θ - 1
csc2θ - 1
Answer explanation
The identity sin²θ + cos²θ = 1 can be rearranged to sin²θ = 1 - cos²θ. Thus, the correct choice is 1 - cos²θ.
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