Trigonometric Identities Review

Trigonometric Identities Review

9th - 12th Grade

10 Qs

quiz-placeholder

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Trigonometric Identities Review

Trigonometric Identities Review

Assessment

Quiz

Mathematics

9th - 12th Grade

Hard

CCSS
HSA.APR.C.4

Standards-aligned

Created by

Amanda Funk

Used 3+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To multiply the expression \( \frac{\frac{1}{\sin x}}{\cos x} \), we rewrite it as \( \frac{1}{\sin x} \cdot \frac{1}{\cos x} \). Thus, the correct choice is \( \frac{1}{\sin x} \cdot \frac{1}{\cos x} \).

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To simplify \( \frac{\sin x}{\frac{1}{\cos x}} \), multiply by the reciprocal: \( \sin x \cdot \cos x \). Thus, the correct choice is \( \sin x \cdot \cos x \).

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

The common denominator for \( \frac{1}{\cos^2x} + \frac{1}{\sin^2x} \) is the product of the individual denominators, which is \( \cos^2x \cdot \sin^2x \). Thus, the correct answer is \( \cos^2x \cdot \sin^2x \).

4.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Select ALL that are a variation of a Pythagorean Identity.

Answer explanation

The Pythagorean identity states \(\sin^2x + \cos^2x = 1\). The equation \(1 - \cos^2x = \sin^2x\) is derived from it. The other options are not valid variations of the Pythagorean identity.

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Pythagorean Identity

Multiply by the conjugate

Factor

Break the fraction apart

Answer explanation

To simplify \( \frac{\sin^2x+1}{\sin x} \), breaking the fraction apart is effective. This allows us to separate it into \( \frac{\sin^2x}{\sin x} + \frac{1}{\sin x} \), simplifying to \( \sin x + \csc x \).

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To simplify \( \frac{\sin x}{\frac{1}{\cos x}} \), multiply by the reciprocal: \( \sin x \cdot \cos x \). Thus, the correct choice is \( \sin x \cdot \cos x \).

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

sin2θ=

1 - cos2θ

1 - sin2θ

sec2θ - 1

csc2θ - 1

Answer explanation

The identity sin²θ + cos²θ = 1 can be rearranged to sin²θ = 1 - cos²θ. Thus, the correct choice is 1 - cos²θ.

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