Equations of a Circle Review

In the equation (x - 3)² + (y - 2)² = 16, the center of the circle is___________.

• (3, 2)

• (-3, -2)

• (-2, -3)

• (2, 3)

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

In the equation (x-4)²+(x-3)²=25, the radius is

• 4
• 3
• 5
• 25

In the equation (x-4)²+(x-3)²=25, the center of the circle is at...

• (-3, -4)
• (4, 3)
• (-4, -3)
• (3, 4)

What is the equation of a circle with radius 2 and center (3, 4)?

• (x+3)² + (y+4)² = 2
• (x-3)² + (y-4)² = 2
• (x+3)² + (y+4)² = 4
• (x-3)² + (y-4)² = 4

What is the equation of a circle with radius 4 and center (0, 8)?

• x² + (y-8)² = 16
• (x-8)² + y² = 4
• x² + (y-8)² = 4
• x² + (y+8)² = 16

What is the center of the circle with equation x² + y² = 1?

• (1, 1)
• (0, 0)
• not enough information

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

See Picture

• A
• B
• C

What is the midpoint between (8, -3) and (2, 5)

• (5, 1)
• (10, 2)
• (-5, -1)
• (3, 4)