SCK Fluid Quiz

A force of 200 N is applied over an area of 0.5 m². What is the pressure exerted on the surface?

• 100 Pa

• 200 Pa

• 400 Pa

• 800 Pa

Answer explanation

p=F/A

p=200/0.5

p=400 Pa

A force of 500N is applied uniformly over an area of 25 cm². What is the pressure?

• 2,000 Pa

• 20,000 Pa

• 200,000 Pa

• 2,000,000 Pa

Answer explanation

A = 25 cm²= 0.0025 m²

^{F = 500N}

^{p = F/A}

p = 500/0.0025

p = 5 000 000/25

p = 200 000 Pa

If the pressure at a point in a fluid is 2000 Pa and the force applied is 400 N, what is the area over which the force is applied?

• 0.1 m²

• 0.2 m²

• 0.3 m²

• 0.4 m²

Answer explanation

p = F/A

2000 = 400/A

2000A = 400

A = 400/2000

A = 0.2 m²

A liquid has a density of 1000 kg/m³. If the liquid column height is 2 m and g = 9.8 m/s², what is the pressure at the bottom of the column?

• 9800 Pa

• 19600 Pa

• 4900 Pa

• 20000 Pa

Answer explanation

A pressure gauge reads 300,000 Pa at a certain depth in a liquid with a density of 1200 kg/m³. What is the depth? (g= 10 m/S²)

• 15 m

• 20 m

• 25 m

• 30 m

Answer explanation

p = ρgh

300 000 = 1200×10×h

300 000 = 12 000 h

h = 300 000/ 12 000

h = 25 m

The pressure at the depth of 3.5 m is 70 kPa (1kPa = 1000 Pa). Find the density of the solution. (g=10 m/s²)

• 7 000 kg/m³

• 700 kg/m³

• 70 kg/m³

• 700 g/cm³

Answer explanation

p = ρgh

70000 = ρ (10) (3.5)

70000/35= ρ

ρ = 2000

A hydraulic system has two pistons. The smaller piston has an area of 0.02 m² and the larger piston has an area of 0.2 m². If a force of 50 N is applied to the smaller piston, what force is exerted by the larger piston?

• 100 N

• 500 N

• 200 N

• 250 N

Answer explanation

A1 = 0.02

A2 = 0.2

F1 = 50 N

F1/A1 = F2/A2

50/0.02 = F2/0.2

2500 = F2/0.2

2500×0.2 = F2

500 = F2

If a hydraulic lift exerts a force of 1000 N on a car, and the area of the larger piston is 2 m², what force is applied to a smaller piston of area 0.5 m²?

• 250 N

• 500 N

• 125 N

• 1000 N

Answer explanation

F1 = 1000 N

A1 = 2

A2 = 0.5

F1/A1 = F2/A2

1000/2 = F2/0.5

500 = F2/0.5

500×0.5 = F2

250 = F2

In a hydraulic press, the area of the smaller piston is 0.1 m² and that of the larger piston is 1 m². If a force of 200 N is applied to the smaller piston, what pressure is transmitted through the fluid?

• 2000 Pa

• 4000 Pa

• 1000 Pa

• 200 Pa

Answer explanation

F1 = 200 N

A1 = 0.1

A2 = 1

F1/A1 = F2/A2

200/0.1 = F2/1

2000 = F2

A hydraulic system has pistons with areas 0.01 m² and 2 m². If the pressure in the system is 20 kPa , what is the force on each piston? (g = 10 m/s²)

• Small Piston = 200 N, large piston = 10 000 N

• Small piston = 2 000 000 N, large piston = 40 000 N

• Small piston = 2000 N, large piston = 40 000 N

• Small piston = 200 N, latge piston = 40 000 N