Solve Polynomial

• a = 0 (repeated)

• a = 1 (repeated)

• a = 1 (repeated), 0 (repeated)

• a = -1 (repeated), 0 (repeated)

Tags

CCSS.HSF-IF.C.7C

• a = 0

• a = 2

• a = -2, 0

• a = 2, 0

Tags

CCSS.HSA-REI.B.4B

Answer explanation

The roots of the polynomial equation can be found by factoring it as (x-1)(x+2)(x-3)=0, giving x=1, -2, 3 as the solutions.

Tags

CCSS.HSA-REI.B.4B

Solve x⁴ - 256 = 0

• x = 4, x = - 4

• x = 4, x = 4i

• x = 4, x -4, x = 4i

• x = 4, x -4, x = 4i,         x = -4i

Tags

CCSS.HSA-REI.B.4B

Solve: -6x-1+5x²=8x²

• x = 5 ±√67 /6

• x = 1, 2/7

• x = 1 ±√ 22

• x = 3 ±√6 / -3

Tags

CCSS.HSA-REI.B.4B

What are the solutions to the polynomial equation?
Choose ALL that apply.

• 2

• -2

• -3

• 3

Solve the following equation:
x⁴ + x² - 90 = 0

• 3, -3, ±√10

• 3, -3

• ±√10

• 3

Tags

CCSS.HSA-REI.B.4B

Factor using technology x³ + 3x² - 6x - 8

• (x+4)(x+1)(x-2)

• (x+4)(x+1)(x+2)

• (x-4)(x-1)(x+2)

• (x-4)(x-1)(x-2)

Tags

CCSS.HSA.APR.B.2

Solve a³-9a²+14a=0.

• -7, -2

• 7, 2

• 0, -7, -2

• 0, 7, 2

Tags

CCSS.HSA-REI.B.4B

Factor Completely: x⁴-9x²

• x²(x+3)(x-3)

• (x²+3x)(x²-3x)

• (x²+9)(x-3)(x+3)

• x²(x²-9)

Tags

CCSS.HSA.APR.C.4