Polynomial Long and Synthetic Division

Is this division problem worked correctly?

• This is correct because if you check the answer with multiplication, you get x²-6x-16

• This is incorrect because 2x should have been subtracted from -6x not added

• This is correct because I said so. PERIODT.

• This is incorrect because the remainder should be zero.

Tags

CCSS.HSA.APR.D.6

What is the proper way to write the answer for the following problem?

• 2x³-x²-25x+12

• 2x⁴-x³-25x²-12x+0

• 2x³-x²-25x-12

• 2x⁴-x³-25x²-12x-0

Tags

CCSS.HSA.APR.D.6

Cam divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Cam wrote the remainder incorrectly.

• Cam did not use a zero place holder for the x³ term.

• Cam added instead of subtracting the rows.

• Cam should have used -2 as his division since the factor was x-2.

Tags

CCSS.HSA.APR.D.6

Was this problem done correctly?

• Yes, because if you multiply the answer, x²-2x-8 by x-3 you will get x³-5x²-2x+24

• No, because you are supposed to change the signs.

• Yes, because if you add all of the numbers together you get 3.

• No because when you multiply 3 times 1 you should write it below the 1 in the problem, then add and drop that answer down.

Tags

CCSS.HSA.APR.D.6

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (5x^3 + 2x^2 - 4x + 1) by the binomial (x + 3).

• 5x^2 - 13x + 35 - 104/(x - 3)

• 5x^2 - 13x + 35 + 104/(x + 3)

• 5x^2 - 13x + 35 - 104/(x + 2)

• 5x^2 - 13x + 35 - 104/(x + 3)

Tags

CCSS.HSA.APR.D.6

• A
• B
• C
• D

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (2x^3 + 4x^2 - 3x + 1) by the binomial (x - 1).

• 2x^2 + 6x - 3

• 2x^2 + 4x + 3

• 2x^2 + 2x + 3

• 2x^2 + 6x + 3

Tags

CCSS.HSA.APR.D.6

Divide using synthetic division

(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4 - 12/(x + 3)

• 2x² - 2x + 6 - 23/(x + 3)

• 2x² - 2x + 8 - 20/(x + 3)

• 2x² - 4x + 1

Tags

CCSS.HSA.APR.D.6

Divide using synthetic division
(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4  R(-12)

• 2x² - 2x + 6  R(-23)

• 2x² - 2x + 8  R(-20)

• 2x² - 4x + 1  R0

Tags

CCSS.HSA.APR.D.6