Application of Exponential

Which of the following function rules describe the data?

Tell wether this function represents growth or decay. (choose all that apply) r is rate of increase/decrease

• Growth

• Decay

• (1-r)

• (1+r)

The population of Pallet Town increases by 15% every year. If there are currently 190,000 people living there, what will be the population in 13 years?

If necessary, round your answer to the nearest whole number.

• 4 people.

• 22,972 people.

• 1,169,030 people.

• 1,188,311 people.

The number of research papers in Professor Sycamore area of expertise has been increasing by 5% every year. Given that 30,010 research papers were published this year. Assuming the trend continues, which equation projects the amount of research papers published in x years?

• y = 30,010 (.05)^x

• y = 30,010 (1.05)^x

• y = 30,010 (.95)^x

• y = 30,010 (5)^x

A sailboat that costs $5,950 decreases in value by 11% per year. How much will the boat be worth after 6 years?

• $5,884.00

• $5,178.97

• $2,992.96

• $2,957.04

The value of a car purchased for $20,000 decreases at a rate of 12% per year. What will be the value of the car after 3 years?

• $12,800.00

• $13,629.44

• $17,600.00

• $28,098.56

Due to its weakening steel industry, Canalave Town has been experiencing a population decline of 10% every year. The current population is 74,000 people. Assuming the trend continues, which equation projects the population in x years?

• y = 74,000 (0.10)^x

• y = 74,000 (0.90)^x

• y = 74,000 (1.10)^x

• y = 74,000 (1.90)^x

A sculpture is increasing in value at a rate of 9% per year, and its value in 2000 was $1500. Write an exponential growth function to model this situation.

• f(t)=1500(1.09)^t

• f(t)=1500(0.09)^t

• f(t)=2000(0.09)^t

• f(t)=1500(9)^t

Most automobiles depreciate as they get older. Suppose an automobile that originally costs $14,000 depreciates by 20% of its value every year. 
What exponential equation can we create to model this situation?

• y=14000(.20)^x

• y=14000(.80)^x

• y=14000(1+.20)^x

• y=14000(1+.80)^x

Most automobiles depreciate as they get older. Suppose an automobile that originally costs $20,000 depreciates by 28% of its value every year.  What is the half-life of this automobile?

• 2 years

• 3 years

• 1/2 years

• 2.11 years