Finding Solutions to Polynomials by Factoring

k²(k-10)(k+10)=0

The solutions are

• 10

• 10 and -10

• 0, 10, -10

Tags

CCSS.HSA-REI.B.4B

If a leading coefficient is negative, before factoring I should

• use AC!

• factor out the negative

Find the zeros of the function and graph.
y=(x + 2)(x - 3)(3x - 5)

• x=-2, x=3, x=5/3

• x=2, x=-3, x=-3/5

• x=2, x=-3, x=5/3

• x=-2, x=3, x=5

Tags

CCSS.HSF-IF.C.7C

Solve by factoring:  2x³+ 7x² + 6x = 0

• x=0, x= 3/2 and x = 2

• x=0, x = -3/2 and x = -2

• x=0, x = 6 and x = 7

• x=2, x = -6 and x = -7

Tags

CCSS.HSF-IF.C.7C

Factor: 27x³ + 8. Then describe how to find the three solutions.

• (3x + 2)(9x² - 6x + 4). Next, set (3x + 2) equal to 0 and solve. Finally, use the Quadratic Formula for (9x² - 6x + 4).

• (9x + 2)(3x² + 18x + 4). Next, set (9x + 2) equal to 0 and solve. Finally, use the Quadratic Formula for (3x² + 18x + 4).

• (3x²+4)(9x + 2). Next, set (3x² + 4) equal to 0 and solve. Finally, set (9x + 2) equal to 0 and solve.

• (27x + 8)(x² - 216x + 64). Next, set (27x + 8) equal to 0 and solve. Finally, use the Quadratic Formula for (x² - 216x + 64).

Tags

CCSS.HSA.APR.C.4

What are the zeros for this function?

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Identify the number of roots:
x³+4x²-11x-30

• 1

• 2

• 3

• 4

What are the zeros for this function?

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Solve the following equation:
x⁴ + x² - 90 = 0

• 3, -3, ±√10

• 3, -3

• ±√10

• 3

Tags

CCSS.HSA-REI.B.4B