Quadratic Graph Forms

• Standard

• Factored

• Vertex

• Parabolic

• (-5, -12)

• (5,-12)

• (5, 12)

• (-5, 12)

• (1, 7)

• (-1, 7)

• (7, 1) 

• (0, 7) 

Which of the following correctly shows the vertex of this graph

• f(x) = (x -5)² + 1

• f(x) = (x - 1)² - 5

• f(x) = (x + 1)² - 5

• f(x) = (x + 5)² +1

The graph of quadratic function f is shown on the grid.

Vertex: (a)  

y-intercept: (b)  

Axis of Symmetry: ​ (c)  

Minimum Value: (d)  

• (-3, -5)

• (0, 4)

• x = -3

• -5

• (-2, -4)

• (-6, 4)

• (4, 0)

• 4

• x = -5

• -4

The graph of quadratic function f is shown on the grid.

f(x) = (x + 3)² − 5

Vertex: (a)  

y-intercept: (b)  

Axis of Symmetry: ​ (c)  

Minimum Value: (d)  

• (-3, -5)

• (0, 4)

• x = -3

• -5

• (-2, -4)

• (-6, 4)

• (4, 0)

• 4

• x = -5

• -4

If we have the equation here, can we graph and match?

(a)  

• F

• G

• H

• J

The graph of quadratic function f is shown on the grid.

Vertex: (a)  

y-intercept: (b)  

Axis of Symmetry: ​ (c)  

Range : (d)  

• (-3, -5)

• (0, 4)

• x = -3

• x ≥ -5

• (-2, -4)

• (-6, 4)

• (4, 0)

• x ≥ 3

• x = -5

• -4

Label the following in the graph:

a

b

d

c

e

root/x-intercept right

axis of symmetry (AOS)

vertex

y-intercept

root/x-intercept left

Tags

CCSS.HSF-IF.C.7A

Looking at the graph,

The vertex is at Point ​ (a)  

The Positive Zero is at Point ​ (b)  

The y-intercept is at Point ​ (c)  

The Negative Zero is a Point ​ (d)  

• 3

• 4

• 2

• 1

• Not Shown

Tags

CCSS.HSF-IF.C.7A