Quadratic Situations Max Height of a Projectile

The height of an object thrown into the air can be modeled by the formula h(t) = -16t² + 70t + 95, where h(t) is in feet after t seconds.
What is the height of the object after 5 seconds?

• 95 feet

• 45 feet

• 70 feet

• 171.56 feet

A ball is thrown into the air with an upward velocity of 100 ft/s. Its height, h, after t seconds is given by the function
 h = -16t² + 64t + 960.
How many seconds did it take for the ball to reach its maximum height?

• 10 seconds

• 64 seconds

• 960 seconds

• 2 seconds

For that same projectile, at what TIME does the maximum height occur? 
h(t) = -16t² + 20t + 6 

• 0 seconds 

• 625 seconds 

• 160 seconds 

• 2 seconds 

An object flies through the air and follows a parabolic path. What does the y-axis represent?

• time

• height from the ground

• horizontal distance

• money

An object flies through the air and follows a parabolic path. Which of these typically represents the x-axis? 

• time 

• height from the ground 

What is the initial (starting) height of an object following this path?  h(t) = -16t² +20t + 6

• -16 feet 

• 0 feet

• 20 feet 

• 6 feet 

So for a projectile whose equation is written in standard form:  y = ax² + bx + c, which letter tells us the starting/initial height? 

• a

• b

• c

• x

If path of a projectile is modeled by: 
h(t) = -16t² + 20t +6, what is the height after 1 second? 

• 6 feet 

• 20 feet 

• 10 feet 

• 4 feet 

To calculate the TIME that a maximum height occurs, you should use: 

• -b/(2a) 

• Quadratic formula 

• the c value 

• 0

To calculate the maximum height, you should: 

• Use the time you got from -b/(2a) and plug it in for each "t" 

• -b/(2a) 

• use the c value 

• use the b value