Find Missing Ratio

Find Missing Ratio

10th Grade

13 Qs

quiz-placeholder

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Find Missing Ratio

Find Missing Ratio

Assessment

Quiz

Mathematics

10th Grade

Practice Problem

Hard

CCSS
HSG.SRT.C.8, HSG.SRT.D.10, HSG.SRT.C.6

+1

Standards-aligned

Created by

Anthony Clark

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13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Choose the correct ratio.

cos(33o)=x/14

sin(33o)=x/14

cos(33o)=14/x

sin(33o)=14/x

Tags

CCSS.HSG.SRT.C.6

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Solve for x. Round to the nearest tenth.

7.5

34.1

14.1

30.1

Tags

CCSS.HSG.SRT.C.8

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Solve for x. Round to the nearest tenth.

11.1

9.3

13.0

5.5

Answer explanation

cos32°=adjacenthypotenuse=x11\cos32\degree=\frac{adjacent}{hypotenuse}=\frac{x}{11}
11cos32°=x11\cdot\cos32\degree=x
x9.3x\approx9.3

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Solve for x. Round to the nearest tenth.

Make sure your calculator is in DEGREE mode.

25.7

35.4

6.4

5.6

Answer explanation

tan65°=oppositeadjacent=12x\tan65\degree=\frac{opposite}{adjacent}=\frac{12}{x}
Switch tan65°\tan65\degree with x.x.
x=12tan65°5.6x=\frac{12}{\tan65\degree}\approx5.6

Tags

CCSS.HSG.SRT.C.8

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Solve for x. Round to the nearest tenth.

40.7

44.6

48.8

8.9

Answer explanation

tan65°=oppositeadjacent=x19\tan65\degree=\frac{opposite}{adjacent}=\frac{x}{19}
19tan65°=x40.719\cdot\tan65\degree=x\approx40.7

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Use SOHCAHTOA to solve for the missing side. Round your answer to the nearest tenth.

44.6

22.7

41.7

38.5

Tags

CCSS.HSG.SRT.C.8

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Use SOHCAHTOA to solve for the missing side. Round your answer to the nearest tenth.

46.1

4.9

16.4

26.9

Tags

CCSS.HSG.SRT.C.8

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