Select the Graph Circle from the Equation Center Radius Form

In the equation (x-4)²+(x-3)²=25, the center of the circle is at...

• (-3, -4)

• (4, 3)

• (-4, -3)

• (3, 4)

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=3

• x²+y²=6

• x²+y²=9

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36

• (x - 5)² + (y + 2)² = 6

• (x + 5)² + (y - 2)² = 36

• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

Tags

CCSS.HSG.GPE.A.1

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Tags

CCSS.HSG.GPE.A.1

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Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25

• (x+3)² + (y-6)² = 25

• (x-3)² + (y+6)² = 45

• (x+3)² + (y-6)² = 5

Tags

CCSS.HSG.GPE.A.1

Find the center and the radius of the circle with equation (x - 4)² + (y - 3)² = 25 ?

• Center: (4, 3)

  Radius: 5 units

• Center: (4, 3)

  Radius: 25 units

• Center: (-4, -3)

  Radius: 25 units

• Center: (-4, -3)

  Radius: 5 units

Tags

CCSS.HSG.GPE.A.1

Which of the following graphs match the equation:

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Tags

CCSS.HSG.GPE.A.1