Equation of Circle Given Endpoints of Diameter

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36

• (x - 5)² + (y + 2)² = 6

• (x + 5)² + (y - 2)² = 36

• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

Find the center of the circle if the endpoints of a diameter of the circle are at (-12, -7) and (3, 5)

• (-9/2, -1)

• (-15/2, -6)

• (9/2, 1)

• (15/2, 6)

Tags

CCSS.HSG.GPE.A.1

Select all the equations for a circle with a diameter of 12.

Tags

CCSS.HSG.GPE.A.1

See Picture

• A

• B

• C

Tags

CCSS.HSG.GPE.A.1

• (x-2)²+y²=234

• (x+2)²+y²=234

• (x-2)²+(y+3)²=225

• (x+2)²+(y-3)²=225

• (x-15)²+(y+3)²=4

Tags

CCSS.HSG.GPE.A.1

Find an equation of the circle whose diameter has endpoints at (-5 , 2) and

(3 , 6).

Tags

CCSS.HSG.GPE.A.1

The endpoints of a diameter of a circle are (3,1) and (9,5). Find the equation of the circle.

• (x − 6)² + (y − 3)² = 13

• (x − 3)² + (y − 6)² = 169

• (x − 5)² + (y − 9)² = 13

• (x − 9)² + (y − 5)² = 42.25

Tags

CCSS.HSG.GPE.A.1

Find the equation of a circle with endpoints of a diameter (−3,1) and (9,-3).

Tags

CCSS.HSG.GPE.A.1

The endpoints of a diameter of a circle are (−3,1) and (9,6).Find the equation of the circle?

• (x−5)²+(y−7/2)²=169/4

• (x−3)²+(y−3)²=169/4

• (x−3)²+(y−7/2)²=169/4

• (x−7/2)²+(y−7/2)²=169/4

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle with the given information?

• A

• B

• C

• D