Solving Trigonometric Identity Equations

Solve: 4sin²x = 3 State all solutions in the interval [0, 2π)

• π/6, 11π/6

• π/3, 2π/3

• π/6, 5π/6, 7π/6, 11π/6

• π/3, 2π/3, 4π/3, 5π/3

Tags

CCSS.HSF.TF.B.7

• A
• B
• C
• D

Tags

CCSS.HSF.TF.B.7

• A
• B
• C
• D

Tags

CCSS.HSF.TF.B.7

Choose a good way to start solving this equation

tanx sin²x = 2 tanx

• divide tanx from both sides

• factor out tanx

• subtract 2 tanx from the left and then factor tanx out

• cancel sin²x out

• I have no idea

Tags

CCSS.HSF.TF.B.7

Which of these is equivalent to 2cos²x − 3cosx = 0 ?

• -cos²x = 0

• cosx(2cosx + 3) = 0

• cosx(2cosx − 3) = 0

• cos x = ⅔

Tags

CCSS.HSF.TF.B.7

Solve sinθ = ½ on θ∈[0, 2π)

• θ = π / 6,  7π / 6

• θ = π / 6,  5π / 6

• θ = 5π / 6,  7π / 6

• θ = 7π / 6,  11π / 6

Tags

CCSS.HSF.TF.B.7

Solve for x

don't forget cot = cos/sin

• π

• π/3

• π/2

• -π

Tags

CCSS.HSF.TF.B.7

Solve
cos²θ = ½ 
on θ∈[0, 2π)

• θ = π /4, 7π /4

• θ = π /4, 3π /4

• θ = 3π /4, 5π /4

• θ = π /4, 3π /4, 5π /4, 7π /4

Tags

CCSS.HSF.TF.B.7

2 sinθ+3=2

• π/6,2π/3

• 7π/6 

• 7π/6, 11π/6

Tags

CCSS.HSF.TF.B.7

Which is a correct way to solve the equation

cosx(2cosx − 3) = 0?

• divide cos x from both sides

• set each factor equal to 0 and solve

• distribute cosx into the parentheses

• guess and hope for the best

Tags

CCSS.HSF.TF.B.7