Systems of Equations Review

Systems of Equations Review

9th Grade

20 Qs

quiz-placeholder

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Systems of Equations Review

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Assessment

Quiz

Mathematics

9th Grade

Hard

CCSS
8.EE.C.8B, HSA.CED.A.3, HSA.REI.C.9

+2

Standards-aligned

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve by elimination
-2x + 6y = 16
-4x - 3y = 2

(2,2)

(-2, -2)

(-2,2)

(2,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 4x + 8y = 20
-4x + 2y = -30

(-7,1)

(2,-5)

(-2,5)

(7,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The solution to a system of equations is any ordered pair that makes both equations true. 

TRUE

FALSE

Tags

CCSS.HSA.REI.C.9

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the solution? 

1

-2

(1, 2)

(1, -1)

Tags

CCSS.8.EE.C.8B

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Solve the system. 

(5, -6, 3)

(2, 3, -1)

(-4, 2, 5)

No Solution

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?

4y = 3x + 64

8y = x + 68

4y = 3x + 64

8y = x + 60

3x + 4y = 64

x + 8y = 68

3x + 4y = 64

x + 8y = 60

Tags

CCSS.HSA.CED.A.3

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $68 for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?

4y = 3x + 64

8y = x + 68

4y = 3x + 64

8y = x + 60

3x + 4y = 64

x + 8y = 68

3x + 4y = 64

x + 8y = 60

Tags

CCSS.HSA.CED.A.3

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