
Finding Mean and Standard Deviation of a Sample
Authored by Anthony Clark
Mathematics
12th Grade

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18 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
To test a claim about a mean, when the population standard deviation is unknown we use:
z procedures
Pythagorean Theorem
t procedures
np > 10 and n(1-p) > 10
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
These symbols represent the mean and standard deviation for which of the following distributions?
The Population
The Sample
The Sampling Distribution
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The Gallup Poll asked a random sample of 1785 adults whether they attended church during the past week. Let p-hat be the proportion of people in the sample who attended church. A newspaper report claims that 40% of all U.S. adults went to church last week. Suppose this claim is true.
Calculate the standard deviation of the sampling distribution.
0.0116
0.0117
0.0118
0.0119
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The set of the weights of professional football players was found to have a mean of 275 lbs. with a standard deviation of 5 lbs. If there are a total of 1,650 pro football players in the US, what is the minimum number that weigh between 250 and 300 lbs.?
96%
75%
93.75%
88.89%
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If test scores for a class are: 100, 100, 90, 90, 80, 80, 70, 70, 60, and 60, what are the mean and sample standard deviation?
mean = 80, stdev = 14.9
mean = 70, stdev = 14.9
mean = 80, stdev = 13.9
mean = 80, stdev = 12.9
mean = 85, stdev = 14.9
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Suppose the heights of adult men are normally distributed. The heights of a sample of 30 men are shown below in inches. Compute the mean of the sample.
71
70
69
68
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The term "snowstorms of note" applies to all snowfalls over 6 inches. The snowfall amounts for snowstorms of note in Utica, New York, over a four-year period are as follows: 7.1, 9.2, 8.0, 6.1, 14.4, 8.5, 6.1, 6.8, 7.7, 21.5, 6.7, 9.0, 8.4, 7.0, 11.5, 14.1, 9.5, 8.6 What are the mean and population standard deviation for these data, to the nearest hundredth?
mean = 9.46; standard deviation = 3.74
mean = 9.46; standard deviation = 3.85
mean = 9.45; standard deviation = 3.74
mean = 9.45; standard deviation = 3.85
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