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Chemistry Spring Final Math Review

Authored by Jamie [HHS]

Chemistry

10th Grade

NGSS covered

Used 1+ times

Chemistry Spring Final Math Review
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15 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

A student is analyzing a compound that contains 52.2% carbon, 13.0% hydrogen, and 34.8% oxygen by mass. Determine the empirical formula of the compound.

C4H10O2

C2H6O

C4H11O2

C3H9O

Answer explanation

To find the empirical formula, convert the percentages to moles: C (52.2g/12.01), H (13.0g/1.008), O (34.8g/16.00). This gives approximately 4.36 C, 12.87 H, and 2.18 O. Dividing by the smallest (2.18) yields C2H6O, the correct empirical formula.

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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Using the empirical formula (C2H6O) and the given molar mass, determine the molecular formula. The molar mass of the compound is 92 g/mol.

C8H20O4

C4H12O2

C8H24O4

C5H16O2

Answer explanation

To find the molecular formula, divide the molar mass (92 g/mol) by the empirical formula mass (46 g/mol for C2H6O). This gives 2, so multiply the subscripts in the empirical formula by 2, resulting in C4H12O2.

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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Using the molecular formula C4H12O2, how many molecules are present in a 138 grams sample of this compound?

6.02 x 10^23 molecules

1.38 x 10^24 molecules

1.23 x 10^23 molecules

Answer explanation

To find the number of molecules in 138 grams of C4H12O2, first calculate its molar mass (C: 12.01, H: 1.01, O: 16.00) = 88.16 g/mol. Then, use the formula: molecules = (mass/molar mass) x Avogadro's number = (138 g / 88.16 g/mol) x 6.02 x 10^23 = 9.03 x 10^23 molecules.

Tags

NGSS.HS-PS1-7

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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What is the percent composition of iron in the compound Fe2O3?

69.94%

30.06%

55.95%

34.97%

Answer explanation

To find the percent composition of iron in Fe2O3, calculate the molar mass: Fe (55.85 g/mol) x 2 + O (16.00 g/mol) x 3 = 159.70 g/mol. The percent composition of iron is (2 x 55.85 / 159.70) x 100 = 69.94%.

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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When 8.00 grams of hydrogen gas (H2) react with excess oxygen gas (O2), how many grams of water (H2O) should theoretically be produced?

18.0 grams

36.0 grams

71.5 grams

144.0 grams

Answer explanation

To find the mass of water produced, use the reaction: 2 H2 + O2 -> 2 H2O. 8.00 g H2 (4 moles) produces 4 moles of H2O. The molar mass of H2O is 18 g/mol, so 4 moles x 18 g/mol = 72 g. The closest answer is 71.5 grams.

Tags

NGSS.HS-PS1-7

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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If 70.0 grams of water are actually collected, what is the percent yield of the reaction?

92.3%

97.9%

100%

94.6%

Answer explanation

To find the percent yield, divide the actual yield (70.0 g) by the theoretical yield and multiply by 100. If the theoretical yield is 71.4 g, then (70.0 g / 71.4 g) x 100 = 97.9%. Thus, the correct answer is 97.9%.

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

0.625 mol NaCl

625 mol NaCl

36.5 g NaCl

0.04 mol NaCl

Answer explanation

To find moles of NaCl, use the formula: mol = M × L. Here, M = 5.00 M and L = 0.125 L. Thus, mol = 5.00 × 0.125 = 0.625 mol. Therefore, the correct answer is 0.625 mol NaCl.

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