Limiting Reactants and Percent Yield

Quiz
•
Science
•
12th Grade
•
Hard
Standards-aligned
Lisa Thompson
FREE Resource
15 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
When the limiting reactant is used up, what happens?
the reaction speeds up
the reaction slows down
the reaction moves to its 2nd stage
the reaction stops
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What are the correct steps for determining the limiting reactant?
divide each reactant by its molar mass and look for the smallest number
balance the chemical equation and look for the smallest coefficient
divide the moles of each reactant by its coefficient and look for the smallest number
divide each reactant by Avogadro's number and look for the smallest number
Tags
NGSS.HS-PS1-7
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
True or False?
A chemical reaction stops before the limiting reagent is used up.
True
False
Tags
NGSS.HS-PS1-7
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
When does a reaction stop?
When it wants to
When both the limiting and excess reactants are gone
When all the excess reactant has been consumed
When all the limiting reactant has been consumed
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the limiting reactant if 10 moles of NH3 react with 30.0 moles of NO?
4NH3+6NO --> 5N2 + 6H2O
NH3
NO
N2
water
Tags
NGSS.HS-PS1-7
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the limiting reactant if 15 moles of NH3 react with 16 moles of NO?
4NH3+6NO --> 5N2 + 6H2O
NH3
NO
N2
water
Tags
NGSS.HS-PS1-7
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the limiting reactant if 15 GRAMS of NH3 react with 16 GRAMS of NO?
4NH3+6NO --> 5N2 + 6H2O
(Remember, convert grams to moles, then divide each substance by the number of moles given as the coefficient from the balanced chemical equation).
NH3 is the limiting because the reaction only requires 0.22 mol of NH3
NO is the limiting reactant because the reaction only requires 0.088 mol NO
NH3 is the limiting because the reaction only requires 0.88 mol of NH3
NO is the limiting reactant because the reaction only requires 0.53 mol NO
Tags
NGSS.HS-PS1-7
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