Simple Harmonic Motion Period

For a system in simple harmonic motion, which of the following is the number of cycles or vibrations per unit of time?

• amplitude

• period

• frequency

• revolution

Tags

NGSS.HS-PS4-1

A pendulum swings back and forth 10 times in 12.1 s. What is the frequency?

• 12.1 Hz

• 1..21 Hz

• 0.121 Hz

• 0.826 Hz

• 8.26 Hz

The period of a pendulum may be decreased by

• Increasing the mass of the bob

• moving the equilibrium point

• decreasing the mass of the bob

• shortening the length of pendulum

A pair of trapeze performers at the circus is swinging from ropes attached to a large elevated platform. Suppose that the performers can be treated as a simple pendulum with a length of 16 m. Determine the period for one complete back and forth cycle.

• 2 sec

• 12 sec

• 8 sec

• 10 sec

Tags

NGSS.HS-PS3-2

A pendulum is 0.75 meters long and has a period of 4.17 seconds. The Pendulum is on an unknown planet.  What is the gravity of the Unknown Planet?

• 9.8

• 3.4

• 1.7

• Greater than 9.8

Tags

NGSS.HS-PS2-4

If the length of a simple pendulum is doubled, its period will: 

• halve 

• increase by a factor of sqrt(2) 

• decrease by a factor of sqrt(2)

• double 

Increasing which of the following will increase the frequency of a spring-mass oscillator? (SELECT ALL THAT APPLY.)

• Spring constant

• Mass

• Amplitude

• Gravitational field strength

• Period

Tags

NGSS.HS-PS4-1

A trapeze artist swings in simple harmonic motion with a period of 3.8 s. Calculate the length of the cables supporting the trapeze.

• 3.6 m

• 5.2 m

• 4.1 m

You are designing a pendulum clock to have a period of 1.0 s. How long should the pendulum be?

• 0.25 m

• 1.2 m

• 0.027 m

What is the period of a simple harmonic oscillator with a mass of 2 kg and a spring constant of 8 N/m?

• 1 s

• 2 s

• 3 s

• 4 s