202 Electrical Science (Test Yourself Questions) and "Worked"

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202 Electrical Science (Test Yourself Questions) and "Worked"

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MULTIPLE SELECT QUESTION

45 sec • 1 pt

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
a) Volume of the load

12m²

12m³

12 metres squared

12 metres cubed

FILL IN THE BLANK QUESTION

1 min • 1 pt

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
b) Mass of the load (1dp)

FILL IN THE BLANK QUESTION

1 min • 1 pt

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
c) Weight or force of the load (Nearest whole number)

Answer explanation

Weight or force of the load
force = mass x acceleration
So 15.6x9.81=153N

MULTIPLE CHOICE QUESTION

30 sec • Ungraded

EXAM TIP
Remember, acceleration here is due to the pull of
gravity and is, on average, 9.81 m/s² on Earth.

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FILL IN THE BLANK QUESTION

1 min • 1 pt

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
d) Energy to raise the load (Nearest whole number)

Answer explanation

energy = force × distance
energy = 153 × 72 = 11016J
energy=acceleration×mass×distance
energy = 9.81×15.6×72=11018.592J
∴ The answer is 11019 or 11016 depending on where you start rounding your calculations.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
e) Power to raise the load (1dp)

Answer explanation

FILL IN THE BLANK QUESTION

1 min • 1 pt

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
f) Speed or velocity of the load (1dp)

Answer explanation

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202 Electrical Science (Test Yourself Questions) and "Worked"

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
a) Volume of the load

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
b) Mass of the load (1dp)

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
c) Weight or force of the load (Nearest whole number)

Weight or force of the load
force = mass x acceleration
So 15.6x9.81=153N

EXAM TIP
Remember, acceleration here is due to the pull of
gravity and is, on average, 9.81 m/s² on Earth.

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
d) Energy to raise the load (Nearest whole number)

energy = force × distance
energy = 153 × 72 = 11016J
energy=acceleration×mass×distance
energy = 9.81×15.6×72=11018.592J
∴ The answer is 11019 or 11016 depending on where you start rounding your calculations.

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
e) Power to raise the load (1dp)

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
f) Speed or velocity of the load (1dp)

1. A load, having a mass of 140 kg, is to be raised a distance of 80 m in 2 minutes. How much power is needed to complete this task? (1dp)

Worked example
Using Ohm's Law, what is the power of a circuit having 45 MV and 50 kA?
So: 45 MV is 45,000,000 V (or 45 x 10⁶ V)
And 50 kA is 50,000 A (or 50 x 10³ A)
So, on a calculator: 4 5 x10⁶ X 50 x10³=2.25 x10¹²or 2.25 TW
(or even 2,250,000,000,000 W).

EXAM TIP
If your calculator gives you an answer in a format that doesn’t suit, use the "ENG" button, as this expresses the same answer into different indices. Use the "SHIFT" button directly to move down in indices and shift "ENG" to move up the indices.

Access all questions and much more by creating a free account

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202 Electrical Science (Test Yourself Questions) and "Worked"

Worked ExampleA load, having a density of 1.3 kg/m3 and dimensions of2 m length, 2 m width and a depth of 3 m, needs to belifted a distance of 72 m in a time of 3 minutes. Calculatethe following values:a) Volume of the load

Worked ExampleA load, having a density of 1.3 kg/m3 and dimensions of2 m length, 2 m width and a depth of 3 m, needs to belifted a distance of 72 m in a time of 3 minutes. Calculatethe following values:b) Mass of the load (1dp)

Worked ExampleA load, having a density of 1.3 kg/m3 and dimensions of2 m length, 2 m width and a depth of 3 m, needs to belifted a distance of 72 m in a time of 3 minutes. Calculatethe following values:c) Weight or force of the load (Nearest whole number)

Weight or force of the loadforce = mass x accelerationSo 15.6x9.81=153N

EXAM TIP Remember, acceleration here is due to the pull ofgravity and is, on average, 9.81 m/s2 on Earth.

Worked ExampleA load, having a density of 1.3 kg/m3 and dimensions of2 m length, 2 m width and a depth of 3 m, needs to belifted a distance of 72 m in a time of 3 minutes. Calculatethe following values:d) Energy to raise the load (Nearest whole number)

energy = force × distanceenergy = 153 × 72 = 11016J energy=acceleration×mass×distanceenergy = 9.81×15.6×72=11018.592J∴ The answer is 11019 or 11016 depending on where you start rounding your calculations.

Worked ExampleA load, having a density of 1.3 kg/m3 and dimensions of2 m length, 2 m width and a depth of 3 m, needs to belifted a distance of 72 m in a time of 3 minutes. Calculatethe following values:e) Power to raise the load (1dp)

Worked ExampleA load, having a density of 1.3 kg/m3 and dimensions of2 m length, 2 m width and a depth of 3 m, needs to belifted a distance of 72 m in a time of 3 minutes. Calculatethe following values:f) Speed or velocity of the load (1dp)

1. A load, having a mass of 140 kg, is to be raised a distance of 80 m in 2 minutes. How much power is needed to complete this task? (1dp)

Worked exampleUsing Ohm's Law, what is the power of a circuit having 45 MV and 50 kA?So: 45 MV is 45,000,000 V (or 45 x 106 V)And 50 kA is 50,000 A (or 50 x 103 A)So, on a calculator: 4 5 x106 X 50 x103 =2.25 x1012 or 2.25 TW(or even 2,250,000,000,000 W).

EXAM TIPIf your calculator gives you an answer in a format that doesn’t suit, use the "ENG" button, as this expresses the same answer into different indices. Use the "SHIFT" button directly to move down in indices and shift "ENG" to move up the indices.

Access all questions and much more by creating a free account

Popular Resources on Wayground

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
a) Volume of the load

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
b) Mass of the load (1dp)

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
c) Weight or force of the load (Nearest whole number)

Weight or force of the load
force = mass x acceleration
So 15.6x9.81=153N

EXAM TIP
Remember, acceleration here is due to the pull of
gravity and is, on average, 9.81 m/s² on Earth.

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
d) Energy to raise the load (Nearest whole number)

energy = force × distance
energy = 153 × 72 = 11016J
energy=acceleration×mass×distance
energy = 9.81×15.6×72=11018.592J
∴ The answer is 11019 or 11016 depending on where you start rounding your calculations.

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
e) Power to raise the load (1dp)

Worked Example
A load, having a density of 1.3 kg/m³ and dimensions of
2 m length, 2 m width and a depth of 3 m, needs to be
lifted a distance of 72 m in a time of 3 minutes. Calculate
the following values:
f) Speed or velocity of the load (1dp)

Worked example
Using Ohm's Law, what is the power of a circuit having 45 MV and 50 kA?
So: 45 MV is 45,000,000 V (or 45 x 10⁶ V)
And 50 kA is 50,000 A (or 50 x 10³ A)
So, on a calculator: 4 5 x10⁶ X 50 x10³=2.25 x10¹²or 2.25 TW
(or even 2,250,000,000,000 W).

EXAM TIP
If your calculator gives you an answer in a format that doesn’t suit, use the "ENG" button, as this expresses the same answer into different indices. Use the "SHIFT" button directly to move down in indices and shift "ENG" to move up the indices.