Remainder theorem

Yes, x-3 is a factor of p(x) since the remainder is 0.

No, x-3 is not a factor of p(x) since the remainder is 0.

x-2 is not a factor of $$x^2-3x+5$$   since the remainder is 3.

x-2 is a factor of $$x^2-3x+5$$   since the remainder is 3.

2x - 3 is a factor of p(x).

x-1 is a factor of p(x).

x is a factor of p(x).

x - 3 is a factor of p(x).

1 is a solution of p(x)

1 is not a solution of p(x)

x -1 is a factor of p(x)

x+1 is not a factor of p(x)

x + 2...

The remainder is...

-2...

The work provided shows the polynomial 5x² - 10x - 40 being divided by...

2 is a solution of $$x^2-3x+5$$   since the remainder is 3.

2 is not a solution of $$x^2-3x+5$$   since the remainder is 3.

x+6 is a factor of $$x^3-x^2-40x\ +13$$  .

x+6 is not a factor of $$x^3-x^2-40x\ +13$$  .

x-6 is not a factor of $$x^3-x^2-40x\ +13$$  .

x-6 is a factor of $$x^3-x^2-40x\ +13$$  .

x-7 is a factor of p(x).

x+7 is a factor of p(x).

-7 is a solution of p(x).

7 is a solution of p(x).

x-1 is a factor of p(x).

2x - 3 is a factor of p(x).

x is a factor of p(x).

x - 3 is a factor of p(x).