Water Potential Practice

Determine the net direction in which water moves.

• From an area of high concentration to am an area of low concentration

• From an area of low concentration to an area of high concentration

Hypertonic solutions have ______ solute and _____ water.

• more solute and less water.

• less solute and more water.

• more solute and more water.

• less solute and less water.

Hypotonic solutions have _____ solute and _____ water.

• less solute and more water

• more solute and less water

• less solute and less water

• more solute and more water

What is the formula for calculating water potential?

• Ψ = Ψs + Ψp

• Ψ = Ψs - Ψp

• Ψ = Ψp - Ψs

• Ψ = Ψs * Ψp

When is the water potential inside a cell equal to the water potential outside the cell?

• When there is no net movement of water across the cell membrane.

• When the solute potential is zero.

• When the water potential gradient is at its maximum.

A cell with a water potential of -2.2 bars is placed in a beaker of pure water. In which direction will water move?

• Into the cell

• Out of the cell

• No net movement

• Not enough information

A cell with a water potential of -2.2 bars is placed in a beaker of sucrose solution of -5 bars. Determine the direction of water movement.

• Water moves out of the cell into the sucrose solution.

• Water moves from the sucrose solution into the cell.

• No net movement of water.

• Water moves equally in both directions.

Osmolarity is the total solute concentration within a specific volume of a solvent expressed in osmoles per liter (Osm/L). Based on this definition, water moves:

• From a high osmolarity solution to a low osmolarity solution

• From a low osmolarity solution to a high osmolarity solution

Look at the graph and identify the concentration of the potato at equilibrium.

• O M

• 0.35 M

• 0.4 M

• You cannot determine the concentration of the potato at equilibrium

Determine which solutions are hypertonic relative to the potato.

• 0 M and 0.2 M because the potato gained mass in these solutions.

• 5, 10, 15 ,and 20 because the potato gained mass in these solutions.

• 0.4 M and 0.8 M because the potato lost mass in these solutions.

• -5, -10, -15, and -20 because the potato lost mass in these solutions.