Easy Trigonometric Identities Quiz

$$\sin^2 \theta + \cos^2 \theta = 1$$

$$\tan^2 \theta + 1 = \sec^2 \theta$$

$$\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}$$

$$\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}$$

$$\csc \theta = \frac{1}{\sin \theta}$$

$$\sec \theta = \frac{1}{\cos \theta}$$

$$\cot \theta = \frac{1}{\tan \theta}$$

$$\tan \theta = \frac{\sin \theta}{\cos \theta}$$

$$\tan \theta = \frac{\cos \theta}{\sin \theta}$$

$$\tan \theta = \sin \theta \cdot \cos \theta$$

$$\tan \theta = \frac{\sin \theta}{\cos \theta}$$

$$\tan \theta = \sin^2 \theta + \cos^2 \theta$$

$$\sec \theta = \frac{1}{\sin \theta}$$

$$\sec \theta = \frac{1}{\cos \theta}$$

$$\sec \theta = \frac{1}{\tan \theta}$$

$$\sec \theta = \sin \theta \cdot \cos \theta$$

$$\cot \theta = \frac{\sin \theta}{\cos \theta}$$

$$\cot \theta = \frac{\cos \theta}{\sin \theta}$$

$$\cot \theta = \sin \theta \cdot \cos \theta$$

$$\cot \theta = \frac{1}{\tan \theta}$$

$$\csc \theta = \frac{1}{\sin \theta}$$

$$\csc \theta = \frac{1}{\cos \theta}$$

$$\csc \theta = \frac{1}{\tan \theta}$$

$$\csc \theta = \sin \theta \cdot \cos \theta$$

$$1 + \tan^2 \theta = \sec^2 \theta$$

$$1 + \cot^2 \theta = \csc^2 \theta$$

$$\sin^2 \theta + \cos^2 \theta = 1$$

All of the above

$$\sin^2 \theta = 1 - \cos^2 \theta$$

$$\sin^2 \theta = \cos^2 \theta - 1$$

$$\sin^2 \theta = \tan^2 \theta + 1$$

$$\sin^2 \theta = \sec^2 \theta - 1$$

$$\cos^2 \theta = 1 - \sin^2 \theta$$

$$\cos^2 \theta = \sin^2 \theta - 1$$

$$\cos^2 \theta = \tan^2 \theta + 1$$

$$\cos^2 \theta = \csc^2 \theta - 1$$

$$\tan^2 \theta = \sec^2 \theta - 1$$

$$\tan^2 \theta = 1 - \sec^2 \theta$$

$$\tan^2 \theta = \sec^2 \theta + 1$$

$$\tan^2 \theta = 1 + \sec^2 \theta$$