AlF3 Lewis Structure and Valence Electrons

This video tutorial explains how to write the Lewis structure for aluminum fluoride (AlF3). It begins by counting the valence electrons for aluminum and fluorine, then places the least electronegative element, aluminum, at the center. The tutorial demonstrates how to distribute electrons to form chemical bonds and complete the octets for fluorine atoms. It also highlights that aluminum is an exception to the octet rule, requiring only six valence electrons. The video concludes with a complete Lewis structure for AlF3.

What is the total number of valence electrons in AlF3?

• 27

• 21

• 24

• 18

Which element is placed at the center of the AlF3 Lewis structure?

• Fluorine

• Oxygen

• Aluminum

• Nitrogen

How many electrons are used to form a single bond between aluminum and fluorine?

• Two

• Three

• One

• Four

What is the total number of valence electrons used in the AlF3 structure?

• 18

• 24

• 30

• 21

Why does aluminum not require a full octet in the AlF3 structure?

• It forms double bonds.

• It is a noble gas.

• It is an exception to the octet rule.

• It has more than eight valence electrons.

How many valence electrons does each fluorine atom have in the AlF3 structure?

• Five

• Seven

• Eight

• Six

What is the significance of the octet rule in the context of the AlF3 Lewis structure?

• It is only applicable to fluorine atoms.

• It is an exception for aluminum.

• It ensures all atoms have eight electrons.

• It is not applicable to any atoms.