MCQ on Engineering Physics

An electron and proton have the same de-Broglie wavelength. Then the kinetic energy of the electron is

• Zero

• Infinity

• Equal to the kinetic energy of the proton

• Greater than the kinetic energy of the proton

The concept of matter wave was suggested by

• Heisenberg

• De Broglie

• Schrodinger

• Laplace

If an electron and proton have the same de-Broglie wavelength then the relation between kinetic energy of the electron of proton is..

• KE electron = KE Proton

• KE proton>KE electron

• KE electron>KE proton

• KE electron = 2 KE proton

If the kinetic energies of an electron, a proton a neutron and an alpha particle is identical, then who’s de-Broglie wavelength will be maximum

• Electron

• Proton

• alpha -particle

• Neutron

Matter waves are

• Electromagnetic waves

• Longitudinal waves

• Probability waves

• Transverse waves

If the energy of a particle is reduced to half then the percentage increase in the de-Broglie wavelength is about.

• 41%

• 50%

• 29%

• 100%

The wavelength of de Broglie waves is independent of:

• charge

• momentum

• velocity

• mass

A particle of mass m kg and charge q coulomb is accelerated from rest through V volt; then the de Broglie wavelength associated with it is given by:

• λ=h/√(2mq)

• λ=h/√(2mqV)

• λ=2mqV/√h

• λ=√(2mqV)/h

If De Broglie wavelength of proton and alpha particle (alpha particle consists of 2 protons and 2 neutrons) are same the ratio of their velocity of proton to alpha particle will be. Assume that mass of proton= mass of neutron.

• 1:4

• 4:1

• 1:2

• 1:3

Which one of the following particle has highest wavelength if all are moving with equal velocity.

• Proton

• alpha particle

• neutron

• electron