Mass to Mole Stoichiometry

CH₄ + 2 O₂ → CO₂ + 2 H₂O
How many moles of carbon dioxide are produced from the combustion of 110 g of CH₄?

• 13.7 mol
• 2.75 mol
• 6.11 mol
• 6.85 mol

CH₄ + 2 O₂ → CO₂ + 2 H₂O
How many moles of water are produced from the combustion of 110 g of CH₄?

• 13.7 mol
• 2.75 mol
• 6.11 mol
• 6.85 mol

Using the following equation:

Fe₂O₃(s) + 3H₂(g) → 2Fe(s) + 3H₂O(l)

How many moles of iron can be made from 12.0 grams H₂?

• 4 moles Fe

• 6 moles Fe

• 9 moles Fe

• 2 moles Fe

4 Sc + 3 O₂ ----> 2 Sc₂O₃

How many moles of Sc₂O₃ can be formed when 54 grams of Sc reacts completely with O₂?

• 2.4 mol Sc₂O₃

• 0.6 mol Sc₂O₃

• 0.8 mol Sc₂O₃

• 0.3 mol Sc₂O₃

Tags

NGSS.HS-PS1-7

Fe₂O₃ + 3H₂ → 2Fe + 3H₂O

About how many moles of H₂O will be produced from 150 grams of Fe₂O₃?

• 2.8 mol H₂O

• 1.9 mol H₂O

• 0.94 mol H₂O

• 1.4 mol H₂O

Tags

NGSS.HS-PS1-7

Fe₂O₃ + 3H₂ → 2Fe + 3H₂O

About how many moles of Fe will be produced from 150 grams of Fe₂O₃?

• 2.8 mol Fe

• 1.9 mol Fe

• 0.94 mol Fe

• 1.4 mol Fe

Tags

NGSS.HS-PS1-7

Fe₂O₃ + 3H₂ → 2Fe + 3H₂O

About how many moles of Fe will be produced from 15 grams of hydrogen gas?

• 9.9 mol Fe

• 5.0 mol Fe

• 11 mol Fe

• 1.4 mol Fe

For the reaction represented by the equation Cl₂ + 2KBr → Br₂ + 2KCl, how many moles of potassium chloride can be produced from 356 grams potassium bromide?

• 1.50 mol KCl

• 2.99 mol KCl

• 5.98 mol KCl

• 1.34 mol KCl

Tags

NGSS.HS-PS1-7

What is the correct first step in solving any mass‑to‑mole stoichiometry problem?

• Use the mole ratio to convert moles of the given substance to moles of the unknown

• Convert the given mass of a substance into moles

• Convert moles of the unknown substance into grams

• Add the molar masses of all reactants

After converting the given mass to moles, what is the next step in a mass‑to‑mole stoichiometry calculation?

• Convert the moles of the given substance directly into grams of the unknown

• Use the mole ratio from the balanced equation to find moles of the unknown substance

• Add the molar masses of all reactants

• Convert grams of the unknown into moles