Subtracting Mixed Numbers with Borrowing Techniques

Why is it important to add back what you borrow when subtracting fractions?

• To make the fractions improper

• To change the denominators

• To keep the fractions balanced

• To avoid reducing the fractions

Tags

CCSS.7.NS.A.1C

In the example 20 and 1/8 minus 9 and 5/8, what is the first step after realizing you can't subtract 5 from 1?

• Add the fractions directly

• Borrow from the whole number

• Convert to improper fractions

• Find a common denominator

Tags

CCSS.7.NS.A.1C

After borrowing in the example 20 and 1/8 minus 9 and 5/8, what fraction is added to 1/8?

• 8/8

• 1/8

• 7/8

• 9/8

Tags

CCSS.7.NS.A.1C

What is the final reduced form of the fraction in the example 20 and 1/8 minus 9 and 5/8?

• 10 and 1/2

• 10 and 1/5

• 10 and 1/3

• 10 and 1/4

Tags

CCSS.7.NS.A.1C

In the alternative method, what is the shortcut for borrowing when subtracting 27 and 8/9 from 30 and 5/9?

• Add 10 to the numerator

• Add the denominator to the numerator

• Subtract the denominator from the numerator

• Multiply the numerator by 2

Tags

CCSS.7.NS.A.1C

What is the final answer for 30 and 5/9 minus 27 and 8/9 using the alternative method?

• 2 and 1/3

• 2 and 4/3

• 2 and 2/3

• 2 and 3/3

Tags

CCSS.7.NS.A.1C

When subtracting fractions with different denominators, what is the first step?

• Subtract the numerators directly

• Find the least common multiple of the denominators

• Add the fractions first

• Convert to improper fractions

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

In the example 7 and 1/3 minus 4 and 1/12, what is the common denominator used?

• 6

• 3

• 12

• 9

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

What is the final reduced form of the fraction in the example 7 and 1/3 minus 4 and 1/12?

• 2 and 5/12

• 2 and 1/4

• 2 and 1/3

• 2 and 1/2

Tags

CCSS.7.NS.A.1C

In the complex example 22 and 5/8 minus 8 and 6/7, what is the least common multiple of the denominators?

• 72

• 64

• 56

• 48

Tags

CCSS.7.NS.A.1C