Converting Equations in Standard Form

What is the first step in converting standard form to slope-intercept form?

• Subtract the x term from both sides

• Multiply both sides by the coefficient of x

• Divide both sides by the coefficient of y

• Isolate the y variable

What is the purpose of 'railroad tracks' in the conversion process?

• To indicate division

• To separate variables from constants

• To multiply terms

• To add terms

How do you determine the y-intercept in slope-intercept form?

• By multiplying the slope with x

• It's the constant term in the equation

• It's the coefficient of x

• By dividing the x coefficient

What point do you use to write the point-slope form of an equation?

• The origin

• Any point on the line except the y-intercept

• A point with coordinates (2,3)

• The y-intercept

What is the slope in the point-slope form equation derived in the first example?

• -2/3

• -3/2

• 3/2

• 2/3

In the second example, what operation is performed first?

• Adding 5x to both sides

• Dividing both sides by -3

• Subtracting 5x from both sides

• Multiplying both sides by -3

What is the slope of the line in the second example?

• -5/3

• 5/3

• 3/5

• -3/5

How is the y-intercept determined in the second example?

• By dividing 21 by -3

• By multiplying -3 by 7

• By adding 21 to -3

• By subtracting 21 from 3

What change is made to avoid a double negative in the point-slope form equation?

• y minus 2 becomes y plus 2

• x minus 3 becomes x plus 3

• y minus -2 becomes y plus 2

• x minus -3 becomes x plus 3

What is the correct point-slope form equation for the second example?

• y - 2 = 5/3(x + 3)

• y - 2 = -5/3(x + 3)

• y + 2 = 5/3(x - 3)

• y + 2 = -5/3(x - 3)