Evaluating Integrals with Substitution

Evaluating Integrals with Substitution

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to evaluate a definite integral using the substitution method. It begins by introducing the integral from 0 to 2 of e to the negative 7x and explains the need for substitution by letting u equal the exponent. The tutorial covers finding the differential u, rewriting the integral in terms of u, and solving for dx. It discusses evaluating the integral with new limits of integration for u and finding the antiderivative to calculate the exact value. The video concludes by comparing the results of evaluating the integral with respect to u and x, emphasizing the importance of choosing the correct limits of integration.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral that needs to be evaluated in the problem?

Integral from 0 to 2 of e to the negative x dx

Integral from 0 to 2 of e to the x dx

Integral from 0 to 2 of e to the negative 7x dx

Integral from 0 to 2 of e to the 7x dx

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the substitution method, what is u defined as?

The exponent of x

The exponent of negative 7x

The integral of e to the negative 7x

The derivative of e to the x

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the differential du equal to in terms of dx?

Negative 7 dx

Negative 1/7 dx

7 dx

1/7 dx

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When rewriting the integral in terms of u, what is the expression for dx?

7 du

Negative 1/7 du

Negative 7 du

1/7 du

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the new limits of integration for u when x is 0 and 2?

Negative 7 and negative 14

0 and negative 14

0 and 14

0 and 7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the antiderivative of e to the u with respect to u?

e to the u

Negative 1/7 e to the u

Negative e to the u

1/7 e to the u

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the exact value of the original definite integral?

1/7 e to the 14 minus 1/7

Negative 1/7 e to the negative 14 plus 1/7

1/7 e to the negative 14 minus 1/7

Negative 1/7 e to the 14 plus 1/7

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