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Understanding Derivatives Using the Quotient Rule

Understanding Derivatives Using the Quotient Rule

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
6.EE.A.3

Standards-aligned

Created by

Amelia Wright

FREE Resource

Standards-aligned

CCSS.6.EE.A.3
The video tutorial explains how to determine the derivative of a function using the quotient rule. It begins with an introduction to the problem and the application of the quotient rule, which involves differentiating the numerator and denominator separately. The tutorial then sets up the derivative function and simplifies the expression, focusing on the numerator. Finally, it presents the final derivative expression and demonstrates factoring out the greatest common factor. The tutorial aims to provide a clear understanding of the process of finding derivatives using the quotient rule.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial function given for differentiation?

f(x) = 2x / (2 + 3 cot(x))

f(x) = -2x / (2 - 3 cot(x))

f(x) = -2x / (2 + 3 cot(x))

f(x) = 2x / (2 - 3 cot(x))

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which rule is used to find the derivative of a quotient of two functions?

Power Rule

Product Rule

Quotient Rule

Chain Rule

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the quotient rule, what is the expression for the derivative of u/v?

v * u' - u * v' / v^2

u * v' - v * u' / u^2

u' * v + u * v' / v^2

v' * u - u' * v / u^2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of the numerator -2x in the given function?

-1

0

2

-2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of the constant term 2 in the denominator?

2

0

1

-2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of cotangent x?

-secant squared x

-cosecant squared x

secant squared x

cosecant squared x

Tags

CCSS.6.EE.A.3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of distributing -2 in the expression -2(2 - 3 cot(x))?

-4 + 6 cot(x)

4 - 6 cot(x)

-4 - 6 cot(x)

4 + 6 cot(x)

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