

Projectile Motion and Quadratic Equations
Interactive Video
•
Mathematics, Physics
•
9th - 12th Grade
•
Practice Problem
•
Hard
Mia Campbell
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the equation used to determine the height of a projectile in this problem?
h = -16d^2 + 2d + 5
h = -1/16d^2 + 2d + 5
h = 1/16d^2 - 2d + 5
h = 16d^2 - 2d + 5
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the vertical intercept of the graph represent in this context?
The time taken to reach maximum height
The horizontal distance traveled
The initial height of the projectile
The maximum height of the projectile
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you calculate the initial height of the projectile?
Set d to 0 and solve for h
Set h to 5 and solve for d
Set h to 0 and solve for d
Set d to 1 and solve for h
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the initial height of the projectile when d is zero?
10 feet
5 feet
2 feet
0 feet
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving the quadratic equation for when the projectile reaches 19 feet?
Divide both sides by 16
Multiply both sides by 16
Subtract 19 from both sides
Add 19 to both sides
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why do we multiply both sides of the equation by -16?
To eliminate the constant term
To simplify the equation
To make the leading coefficient positive
To find the maximum height
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the approximate horizontal distance when the projectile first reaches 19 feet?
5.0 feet
10.3 feet
15.7 feet
21.7 feet
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