Integration Techniques and Applications

Integration Techniques and Applications

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
7.NS.A.1C, 8.F.A.3, HSA.APR.D.7

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.7.NS.A.1C
,
CCSS.8.F.A.3
,
CCSS.HSA.APR.D.7
The video tutorial explains how to evaluate a definite integral by first finding the antiderivative using integration formulas. It demonstrates transforming the function into a suitable form for applying the power rule of integration. The tutorial then guides through evaluating the integral at the upper and lower limits, simplifying the result, and interpreting the solution graphically. The area under the curve is shown to represent the value of the definite integral.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in evaluating a definite integral?

Find the derivative of the function.

Graph the function.

Apply the power rule directly.

Find the antiderivative function.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to the Fundamental Theorem of Calculus, how is the definite integral calculated?

By adding the antiderivative at the lower limit to the antiderivative at the upper limit.

By subtracting the antiderivative at the lower limit from the antiderivative at the upper limit.

By multiplying the antiderivative at the lower limit by the antiderivative at the upper limit.

By dividing the antiderivative at the lower limit by the antiderivative at the upper limit.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we need to transform the function before applying the power rule of integration?

To make the function continuous.

To express the function in the form of x raised to the power of n.

To simplify the function.

To change the limits of integration.

Tags

CCSS.7.NS.A.1C

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of applying the integration rule to x raised to the power of -2?

x raised to the power of 0 divided by 0

x raised to the power of -3 divided by -3

x raised to the power of -1 divided by -1

x raised to the power of 1 divided by 1

Tags

CCSS.HSA.APR.D.7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you simplify the expression -1 divided by x?

By moving it to the denominator.

By subtracting 1 from it.

By moving it to the numerator.

By adding 1 to it.

Tags

CCSS.7.NS.A.1C

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the common denominator used to add the fractions -1/5 and 1/2?

20

15

10

5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the definite integral from 2 to 5 of 1 divided by x squared dx?

1/10

3/10

4/10

2/10

Tags

CCSS.8.F.A.3

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