Integration by Substitution Concepts

Integration by Substitution Concepts

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Practice Problem

Hard

Created by

Lucas Foster

FREE Resource

This video tutorial explains the integration by substitution technique, a method useful for integrating composite functions. It begins by identifying the inner function and setting it as U, then finding the differential of U. The tutorial demonstrates how to substitute and integrate in terms of U, and finally, how to simplify the result to find the anti-derivative. The process is compared to the chain rule of differentiation, highlighting the importance of knowing derivative formulas.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main purpose of using integration by substitution?

To simplify the process of differentiation

To solve integrals involving composite functions

To find the limits of integration

To determine the area under a curve

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which rule of differentiation is integration by substitution comparable to?

Product rule

Quotient rule

Chain rule

Power rule

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When choosing a substitution variable 'U', what should it typically represent?

A constant term in the integrand

The inner function of a composite function

The outer function of a composite function

The entire integrand

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the differential 'dU' when U = 5 + x^6?

6x^6 dx

x^5 dx

5x^6 dx

6x^5 dx

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you adjust the integral to match the substitution?

Multiply by a constant

Divide by a constant

Add a constant

Subtract a constant

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral of U^(1/2) with respect to U?

3/2 U^(1/2) + C

1/2 U^(3/2) + C

3/2 U^(2/3) + C

2/3 U^(3/2) + C

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After integrating in terms of 'U', what is the next step?

Differentiate the result

Multiply the result by a constant

Add a constant to the result

Convert the result back to the original variable 'X'

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