Inverse Trigonometric Functions Integration

Inverse Trigonometric Functions Integration

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Amelia Wright

FREE Resource

This video tutorial introduces integration involving inverse trigonometric functions, focusing on pattern recognition to apply integration rules. It covers the formulas for arc sine, arc tangent, and arc secant, explaining why these are preferred over arc cosine, arc cotangent, and arc cosecant in integration. The tutorial provides three examples, demonstrating step-by-step integration using the respective formulas for arc sine, arc tangent, and arc secant, emphasizing the importance of identifying the correct pattern and determining the values of 'a' and 'u' for successful integration.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the key skill emphasized for applying integration rules effectively?

Pattern recognition

Memorization

Speed

Creativity

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which inverse trigonometric function is used when there is no square root in the denominator?

Arc cosine

Arc sine

Arc tangent

Arc secant

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are arc cosine, arc cotangent, and arc cosecant not typically used in integration?

They are too complex

They are the opposites of more commonly used functions

They are not inverse functions

They do not have integration formulas

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the arc sine integration example, what is the value of 'a' when the denominator is the square root of 16 minus x squared?

2

3

5

4

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the anti-derivative of the function with a denominator of a squared plus u squared?

Arc cosine

Arc sine

Arc tangent

Arc secant

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the arc tangent example, what is the value of 'u' if u squared equals 16x squared?

3x

4x

2x

5x

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What adjustment is made in the arc secant example to fit the pattern?

Divide the denominator by 2

Divide the denominator by 3

Multiply the numerator by 3

Multiply the numerator by 2

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