Understanding Null Space and Basis

Understanding Null Space and Basis

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
8.EE.C.8B, 6.EE.C.9

Standards-aligned

Created by

Liam Anderson

FREE Resource

Standards-aligned

CCSS.8.EE.C.8B
,
CCSS.6.EE.C.9
The video tutorial explains how to find a basis for the null space of a matrix. It begins by setting up the augmented matrix for the equation A times vector x equals the zero vector. The tutorial identifies basic and free variables, solves the equations to express variables in terms of the free variable, and parametrizes the solution using a parameter t. Finally, it finds the basis for the null space of the matrix, which is represented by a vector that spans the solution set.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal when finding a basis for the null space of a matrix?

To calculate the inverse of the matrix

To solve the equation A * x = 0

To find the determinant of the matrix

To determine the eigenvalues of the matrix

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the presence of a pivot in a column of a matrix indicate?

The column is an eigenvector

The column is a free variable

The column is a basic variable

The column is redundant

Tags

CCSS.8.EE.C.8B

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which variable is considered a free variable in the given matrix setup?

x1

x2

x3

x4

Tags

CCSS.6.EE.C.9

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve for x1 in terms of the free variable x4?

x1 = 2 * x4

x1 = -1/2 * x4

x1 = 3 * x4

x1 = 1/3 * x4

Tags

CCSS.6.EE.C.9

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the solution for x2 in terms of x4?

x2 = -2/3 * x4

x2 = -1/3 * x4

x2 = 1/2 * x4

x2 = 2/3 * x4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the parameter used to express the solution vector?

v

u

t

s

Tags

CCSS.6.EE.C.9

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for x3 in terms of the parameter t?

x3 = -2 * t

x3 = 1/2 * t

x3 = -1/3 * t

x3 = 2 * t

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