Solving Quadratic Equations and Functions

Solving Quadratic Equations and Functions

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to solve a quadratic equation by performing a substitution to simplify it into a basic quadratic form. The process involves setting the equation to zero, factoring it, and then substituting back to the original variable. The solutions are verified to ensure they satisfy the original equation, resulting in four possible solutions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in recognizing the given equation as a quadratic form?

Solving for x

Graphing the equation

Factoring the equation

Performing a substitution

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is made to simplify the equation into a basic quadratic form?

u = x - 23

u = x^2 + 23

u = x + 23

u = x^2 - 23

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After substitution, what is the next step to solve the quadratic equation?

Set the equation equal to zero

Graph the equation

Add a constant to both sides

Multiply both sides by a constant

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which pair of numbers are the factors of 18 that add up to 11?

7 and 1

9 and 2

5 and 4

6 and 3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of substituting back the original variable into the factored equation?

x^2 + 14 and x^2 + 21

x^2 - 14 and x^2 - 21

x^2 - 23 and x^2 - 9

x^2 + 23 and x^2 + 9

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the solutions for x when x^2 - 14 = 0?

x = ±√23

x = ±√14

x = ±√9

x = ±√21

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the solutions for x when x^2 - 21 = 0?

x = ±√23

x = ±√9

x = ±√21

x = ±√14

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