
Understanding Parametric Equations and Planes
Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Lucas Foster
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main objective of the problem discussed in the video?
To calculate the area of a triangle formed by a line and a plane.
To find the distance between a point and a plane.
To determine the parametric equations of a line through a point and perpendicular to a plane.
To find the intersection of two planes.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the normal vector of a plane represent in relation to a line?
The normal vector is perpendicular to the line.
The normal vector is parallel to the line.
The normal vector is the midpoint of the line.
The normal vector is the endpoint of the line.
Tags
CCSS.4.G.A.1
CCSS.HSG.CO.A.1
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can the normal vector be used to find the direction vector of a line?
By dividing the normal vector by the line's point.
By subtracting the normal vector from the line's point.
By using the normal vector as the direction vector.
By adding the normal vector to the line's point.
Tags
CCSS.4.G.A.1
CCSS.HSG.CO.A.1
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the graphical representation in the video?
It shows the intersection of two lines.
It illustrates the parallel relationship between the line and the normal vector.
It demonstrates the perpendicular relationship between two planes.
It highlights the distance between a point and a plane.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the components of the normal vector used in the video?
(3, 8, 1)
(1, 6, -5)
(3, 6, -1)
(8, 1, 3)
Tags
CCSS.HSA.CED.A.3
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the x-component of the parametric equation for the line determined?
By dividing the x-component of the point by the normal vector's x-component.
By subtracting the x-component of the point from the normal vector's x-component.
By multiplying the x-component of the point by the normal vector's x-component.
By adding the x-component of the point to the normal vector's x-component multiplied by t.
Tags
CCSS.HSA.CED.A.3
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the parametric equation for y(t) in the video?
y(t) = -5 - t
y(t) = 6 + 8t
y(t) = 3 + 6t
y(t) = 1 + 3t
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