Laplace Transforms and Partial Fractions

Laplace Transforms and Partial Fractions

Assessment

Interactive Video

Mathematics, Science

10th Grade - University

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to solve a homogeneous differential equation using the Laplace transform. It begins with applying the Laplace transform to the equation, solving for Y(s), and then using partial fraction decomposition. Finally, the inverse Laplace transform is applied to find the particular solution Y(t). The tutorial highlights the steps and calculations involved in the process.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the given differential equation using Laplace transforms?

Apply the inverse Laplace transform

Substitute initial conditions

Apply the Laplace transform to both sides

Factor the equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which property of Laplace transforms is used to simplify the equation after applying the transform?

Convolution

Differentiation

Linearity

Integration

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What values are substituted for y(0) and y'(0) in the transformed equation?

y(0) = 0, y'(0) = -2

y(0) = -2, y'(0) = 0

y(0) = 2, y'(0) = 0

y(0) = -2, y'(0) = -2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of performing partial fraction decomposition on Y(s)?

To simplify the initial conditions

To facilitate the inverse Laplace transform

To solve for Y(s) directly

To eliminate complex numbers

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for Y(s) after factoring the numerator and denominator?

Y(s) = 2(s + 6)/(s + 2)(s + 4)

Y(s) = -2(s + 6)/(s + 2)(s + 4)

Y(s) = -2(s + 4)/(s + 2)(s + 6)

Y(s) = 2(s + 4)/(s + 2)(s + 6)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'b' in the partial fraction decomposition of Y(s)?

b = -4

b = -2

b = 4

b = 2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'a' in the partial fraction decomposition of Y(s)?

a = 4

a = -4

a = 2

a = -2

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