Gradient and Partial Derivatives

Gradient and Partial Derivatives

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains how to find the gradient of a function f(x, y) = e^(2x) * sin(3y) at the point (2, -2). It reviews the concept of gradients and partial derivatives, then demonstrates the calculation of the gradient's x and y components. The tutorial includes evaluating the gradient at a specific point using substitution and approximating the results with a calculator. Finally, it interprets the gradient's significance, indicating the direction of maximum increase of the function at the given point.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function f(x, y) given in the problem?

e^(2y) * sin(3x)

e^(x) * sin(y)

e^(3x) * sin(2y)

e^(2x) * sin(3y)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the gradient of a function?

A constant function

A scalar value

A matrix of second derivatives

A vector of partial derivatives

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the partial derivative of f with respect to x?

Differentiate with respect to y, treating x as a constant

Integrate with respect to x

Differentiate with respect to x, treating y as a constant

Integrate with respect to y

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the partial derivative of f with respect to y?

3e^(2x) * cos(3y)

2e^(2x) * sin(3y)

3e^(2x) * sin(3y)

e^(2x) * sin(3y)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the x-component of the gradient at the point (2, -2)?

3e^4 * cos(-6)

2e^4 * cos(-6)

2e^4 * sin(-6)

e^4 * sin(-6)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the y-component of the gradient at the point (2, -2)?

3e^4 * cos(-6)

2e^4 * sin(-6)

e^4 * cos(-6)

3e^4 * sin(-6)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of the x-component of the gradient?

60.7890

45.1234

157.2706

30.5111

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