Law of Sines and Triangle Measures

Law of Sines and Triangle Measures

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

CCSS
8.G.A.5, HSG.SRT.C.8, HSG.SRT.D.10

+3

Standards-aligned

Created by

Sophia Harris

FREE Resource

Standards-aligned

CCSS.8.G.A.5
,
CCSS.HSG.SRT.C.8
,
CCSS.HSG.SRT.D.10
CCSS.4.G.A.1
,
CCSS.7.G.A.1
,
CCSS.HSG.SRT.D.11
,
The video tutorial explains how to solve a real-world problem using the Law of Sines. A surveyor needs to find the distance across a river by choosing points A and B on one side and a reference point C on the opposite side. Given the lengths and angles, the tutorial demonstrates setting up a proportion using the Law of Sines, calculating the unknown angle, and solving for the unknown side length. The final calculation reveals the distance across the river to be approximately 127.4 meters.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the problem discussed in the video?

To determine the width of a road

To measure the depth of a lake

To calculate the distance across a river

To find the height of a building

Tags

CCSS.4.G.A.1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which points are chosen by the surveyor on one side of the river?

Points B and C

Points A and B

Points A and C

Points C and D

Tags

CCSS.8.G.A.5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the measure of angle A in the triangle?

47 degrees

90 degrees

82 degrees

51 degrees

Tags

CCSS.8.G.A.5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do we find the measure of angle C?

By using the Pythagorean theorem

By subtracting the measures of angles A and B from 180 degrees

By measuring directly with a protractor

By using the cosine rule

Tags

CCSS.8.G.A.5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the measure of angle C?

60 degrees

82 degrees

47 degrees

51 degrees

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the proportion set up using the Law of Sines?

Sine of 51 degrees divided by 100 meters equals sine of 82 degrees divided by X

Sine of 82 degrees divided by 100 meters equals sine of 51 degrees divided by X

Sine of 51 degrees divided by X equals sine of 82 degrees divided by 100 meters

Sine of 47 degrees divided by 100 meters equals sine of 51 degrees divided by X

Tags

CCSS.7.G.A.1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed after setting up the proportion to solve for X?

Subtraction

Division

Cross multiplication

Addition

Tags

CCSS.HSG.SRT.C.8

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