Understanding Antiderivatives and Constants

Understanding Antiderivatives and Constants

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to find the original function given its derivative and an initial condition. It starts by introducing the problem and the given data, including the derivative and a specific function value. The tutorial then demonstrates finding the antiderivative using the power rule in reverse. It proceeds to determine the constant of integration by substituting the given function value. Finally, the tutorial evaluates the function at a specific point to find the desired result.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial problem statement given in the video?

Find F(2) given f'(x) = 24/x^3

Find F(-1) given F(2) = 12 and f'(x) = 24/x^3

Find the integral of f'(x) = 24/x^3

Find the derivative of F(x) given F(2) = 12

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the original function from its derivative?

Solve for the constant directly

Find the antiderivative of the given derivative

Evaluate the function at x = 2

Differentiate the given function

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which rule is used to find the antiderivative of 24/x^3?

Chain Rule

Product Rule

Quotient Rule

Power Rule in Reverse

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is a constant added when finding the antiderivative?

To account for the initial condition

To simplify the expression

To ensure the function is continuous

To make the function differentiable

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant of integration determined?

By using the given value F(2) = 12

By setting the constant to zero

By evaluating the function at x = -1

By differentiating the function

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for f(x) after incorporating the constant?

f(x) = 24/x^3 + C

f(x) = -12/x^2 + 15

f(x) = -12/x^2 + C

f(x) = 24/x^3 - 15

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of x used to find the constant of integration?

x = 0

x = 2

x = 1

x = -1

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