
Understanding Antiderivatives and Constants
Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Olivia Brooks
FREE Resource
Standards-aligned
Read more
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the initial problem statement given in the video?
Find F(2) given f'(x) = 24/x^3
Find F(-1) given F(2) = 12 and f'(x) = 24/x^3
Find the integral of f'(x) = 24/x^3
Find the derivative of F(x) given F(2) = 12
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in finding the original function from its derivative?
Solve for the constant directly
Find the antiderivative of the given derivative
Evaluate the function at x = 2
Differentiate the given function
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which rule is used to find the antiderivative of 24/x^3?
Chain Rule
Product Rule
Quotient Rule
Power Rule in Reverse
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is a constant added when finding the antiderivative?
To account for the initial condition
To simplify the expression
To ensure the function is continuous
To make the function differentiable
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the constant of integration determined?
By using the given value F(2) = 12
By setting the constant to zero
By evaluating the function at x = -1
By differentiating the function
Tags
CCSS.HSA.REI.A.2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the expression for f(x) after incorporating the constant?
f(x) = 24/x^3 + C
f(x) = -12/x^2 + 15
f(x) = -12/x^2 + C
f(x) = 24/x^3 - 15
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of x used to find the constant of integration?
x = 0
x = 2
x = 1
x = -1
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