
Understanding Visibility and Altitude
Interactive Video
•
Mathematics, Science
•
8th - 12th Grade
•
Practice Problem
•
Hard
+1
Standards-aligned
Ethan Morris
FREE Resource
Standards-aligned
Read more
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the formula used to estimate visibility on a clear day?
v = 1,225 * sqrt(a) / 1,000
v = 1,000 * sqrt(a) / 1,225
v = 1,225 / sqrt(a) * 1,000
v = sqrt(a) / 1,225 * 1,000
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the problem statement, how far can Jerome see?
250 miles
200 miles
150 miles
100 miles
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the visibility in miles when the altitude is unknown?
200 miles
150 miles
100 miles
250 miles
Tags
CCSS.8.EE.A.2
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving for altitude when given visibility?
Isolate the square root of a
Multiply both sides by 1,225
Divide both sides by 1,000
Add 1,000 to both sides
Tags
CCSS.HSA.REI.A.2
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What operation is performed to both sides of the equation to isolate the square root of a?
Addition
Subtraction
Division
Multiplication
Tags
CCSS.7.NS.A.2A
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which numbers are used to simplify the equation by canceling common factors?
6,000 and 49
150 and 1,225
25 and 49
1,000 and 1,225
Tags
CCSS.8.EE.A.2
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the simplified form of the equation before squaring both sides?
49 / 6,000 = sqrt(a)
150 / 1,225 = sqrt(a)
1,225 / 1,000 = sqrt(a)
6,000 / 49 = sqrt(a)
Tags
CCSS.8.EE.A.2
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