Understanding Visibility and Altitude

Understanding Visibility and Altitude

Assessment

Interactive Video

Mathematics, Science

8th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to determine the altitude at which a person can see a certain distance using a given formula. The problem involves calculating the altitude when the visibility is known to be 150 miles. The tutorial walks through the steps of isolating the variable, simplifying the equation, and performing calculations to find the altitude, assumed to be in feet. The final result is approximately 14,993 feet.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to estimate visibility on a clear day?

v = 1,225 * sqrt(a) / 1,000

v = 1,000 * sqrt(a) / 1,225

v = 1,225 / sqrt(a) * 1,000

v = sqrt(a) / 1,225 * 1,000

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the problem statement, how far can Jerome see?

250 miles

200 miles

150 miles

100 miles

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the visibility in miles when the altitude is unknown?

200 miles

150 miles

100 miles

250 miles

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving for altitude when given visibility?

Isolate the square root of a

Multiply both sides by 1,225

Divide both sides by 1,000

Add 1,000 to both sides

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to both sides of the equation to isolate the square root of a?

Addition

Subtraction

Division

Multiplication

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which numbers are used to simplify the equation by canceling common factors?

6,000 and 49

150 and 1,225

25 and 49

1,000 and 1,225

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the simplified form of the equation before squaring both sides?

49 / 6,000 = sqrt(a)

150 / 1,225 = sqrt(a)

1,225 / 1,000 = sqrt(a)

6,000 / 49 = sqrt(a)

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