What is the initial condition given for y(0) in the problem?

Differential Equations with Repeated Roots

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Mathematics
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10th - 12th Grade
•
Hard

Liam Anderson
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
y(0) = 3
y(0) = 4
y(0) = 1
y(0) = 2
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the characteristic equation derived from the given differential equation?
r^2 + r + 0.25
r^2 - r + 0.25
r^2 - r - 0.25
r^2 + r - 0.25
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is a more general solution needed for repeated roots?
Because the initial solution is too complex
Because the initial solution is not general enough for two initial conditions
Because the initial solution is incorrect
Because the initial solution is too simple
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the form of the general solution for repeated roots?
y = c1 * e^(1/2 * x) + c2 * x * e^(1/2 * x)
y = c1 * e^(x)
y = c1 * e^(1/2 * x)
y = c1 * x * e^(1/2 * x)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the derivative of the general solution used to find c1 and c2?
y' = c1 * e^(1/2 * x)
y' = 1/2 * c1 * e^(1/2 * x) + c2 * e^(1/2 * x) + 1/2 * c2 * x * e^(1/2 * x)
y' = c2 * e^(x)
y' = c1 * x * e^(1/2 * x)
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of c1 found using the initial conditions?
c1 = 3
c1 = 2
c1 = 4
c1 = 1
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of c2 found using the initial conditions?
c2 = -1/3
c2 = 2/3
c2 = 1/3
c2 = -2/3
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