Factoring Difficult Trinomials

Factoring Difficult Trinomials

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains how to factor difficult trinomials using the quadratic formula. It begins by introducing the problem of factoring complex trinomials and then demonstrates how to apply the quadratic formula to find solutions. The tutorial walks through solving the quadratic equation step-by-step, finding the factors, and verifying the factored expression. The video concludes by summarizing the process and emphasizing the usefulness of the quadratic formula for factoring challenging trinomials.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in factoring a difficult trinomial like 12x² + 243x - 189?

Find two numbers that multiply to the constant term.

Use the quadratic formula.

Multiply the leading coefficient by the constant term.

Add the coefficients together.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of b in the quadratic formula for the trinomial 12x² + 243x - 189?

12

243

189

2268

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of 243 squared in the quadratic formula?

59049

261

9072

2268

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the two roots obtained from the quadratic formula for the trinomial 12x² + 243x - 189?

2/3 and -20

5/6 and -19

1/2 and -18

3/4 and -21

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you derive the factor x + 21 from the root -21?

Add 21 to both sides of the equation.

Subtract 21 from both sides of the equation.

Multiply both sides by 21.

Divide both sides by 21.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the factor derived from the root 3/4?

x - 3/4

x + 3/4

4x - 3

4x + 3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of adding a 3 to the expression 4x times x?

To make it equal to 12x².

To simplify the expression.

To factor out the greatest common factor.

To eliminate the constant term.

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